# Boats and Streams Aptitude Questions and Answers

## Boats and Streams Aptitude Questions and Answers

Hello friends,

Today we are sharing important notes in Boats and Streams Aptitude Questions and Answers pdf is helpful for all competitive exams like SSC CGL, BANK, RAILWAYS,  RRB NTPC, LIC AAO, and many other exams.Boats and Streams Aptitude Questions and Answers  are very important for any competitive exam and these Boats and Streams Aptitude Questions and Answers is very useful for it. ENGLISH Notes will be very helpful for your examination. all previous year questions are available in this pdf

MyNotesAdda.com is an online Educational Platform, where you can download free PDFs for UPSC, SSC CGL, BANK, RAILWAYS,  RRB NTPC, LIC AAO, and many other exams. SSC CGL, BANK, RAILWAYS,  RRB NTPC, LIC AAO Boats, and Streams Aptitude Questions and Answers

Boats and Streams Aptitude Questions and Answers is a pdf is cover all basic topics. SSC CGL, BANK, RAILWAYS,  RRB NTPC, LIC  his Boats and Streams Aptitude Questions and Answers  pdf is available all basic concepts.

### TOPIC RELATED POSTS

Q1- Ratio between speed of boat in still water to speed of stream is 5 : 2. If 224 km is travelled by downstream in 4 hours then find the difference between speed of boat in still water and speed of stream?
A
24 km/hr
B
22 km/hr
C
28 km/hr
D
26 km/hr
E
30 km/hr
» Explain it
Ans- Correct Option: A
Let the speed of boat in still water and speed of stream be 5x and 2x respectively.

According to the question,

224 = 5x + 2x
4
x = 224 × 4
7
x = 32 = 8
4
Required difference = 5x – 2x = 3x

3x = 24 km/hr

Hence, option A is correct.

Q-2 If the upstream speed of a boat is 50% less than the downstream speed of the boat and if a object is thrown in the river it covers 100m in 50 sec, then how much distance boat can cover in still water in 5 hours?
A
900 km
B
100 km
C
120 km
D
108 km
E
105 km
» Explain it
Ans- Correct Option: D
Let the speed of boat in still water be s m/sec

As the object covers 100m in 50 sec , so the distance travelled by the object will be with the help of the speed of the stream only.

Speed of stream = 100 = 2 m/s
50
Given that,

(s – 2) = (s + 2) – 50 (s + 2)/100

(s – 2) = (s + 2)(1 – 1/2)

s = 6 m/sec

s = 6 × 18 = 108 km/hr
5 5
Distance covered by the boat in still water in 5 hours

= 108 × 5 = 108 km
5
Hence, option D is correct.

Q-3A steamer can go 12 km in still water in 25 minutes. One day, it went 11.25 km upstream and returned the same distance in downstream. If the difference between the time taken to travel upstream and downstream was 12.5 minutes, then what was the speed of stream in km per hour?
A
7.2
B
5.4
C
6.3
D
4.5
E
None of these
» Explain it
Ans- Correct Option: A
In still water, the speed of steamer = 12000
25
= 480 meter per minute = 8 meters per second

Let the speed of stream = v m/sec

In upstream, the speed of steamer = (8 – v) m/sec

In downstream, the speed of steamer = (8 + v) m/sec

According to the question,

11250 – 11250 = 12.5 × 60 = 750 seconds
8 – v 8 + v
By solving, v = 2 meters per second

= 2 × 18 = 7.2 km per hour
5
Hence, option A is correct.

Q- 4The ratio of speed of A and B in still water is 3 : 2. A and B start from the same point in the river, A goes upstream and B goes downstream. After 3 hours the stream stops flowing and A starts rowing in the opposite direction to meet B. How much time after the stream stops flowing does A meet B?
A
16 hrs
B
15 hrs
C
12 hrs
D
18 hrs
E
None of these
» Explain it
Ans- Correct Option: B

Let the speed of current be = c km/hr

Let the speeds of A and B in still water be 3k km/hr and 2k km/hr

Upstream speed of A = (3k – c) km/hr

Downstream speed of B = (2k + c) km/hr

Distance between A and B after 3 hrs = [3 (3k – c) + 3 (2k + c)] km

= (9k – 3c + 6k + 3c) km

= 15k km

After the stream becomes stationary

Relative speed when both go in same direction = (3k – 2k) km/hr = k km/hr

Time after which they meet = 15 k/ k = 15 hrs

Hence, option B is correct.

Q- 5 A boat goes a certain distance upstream and comes back downstream to the starting point in 144 min. If the speed of the boat in still water becomes 66.67% of the original, time taken for the same journey will be 224 min. What is the ratio of the speed of boat in still water and speed of the current?
A
7 : 1
B
6 : 1
C
5 : 3
D
7 : 2
E
None of these
» Explain it
Ans- Correct Option: B
Let the distance be D and Speed of boat in still water be 3B and that of the current be C

D + D = 144 ……….eq.(i)
3B + C 3B – C
When the speed of the boat becomes 66.67% → new boat speed = 2B

D + D = 224 ……….eq.(ii)
2B + C 2B – C
Dividing eq. (i) by eq. (ii)

6B =
(3B + C) (3B – C) 144
4B 224
(2B + C) (2B – C)
6 × (4B2 – C2) = 9
4 × (9B2 – C2) 14
4B2 – C2 = 3
9B2 – C2 7
B2 = 4C2 → B = 2
C 1
3B = 6
C 1
The ratio of the speed of boat and current in 6 : 1

### Boats and Streams Aptitude Questions and Answers

Q6- The speed of current is 5 km/h. What will be the respective downstream speed and upstream speed of a boy rowing a boat, if one third of the distance covered going downstream in a certain time is equal to the distance covered going upstream in the same time.
A
15 km, 5 km
B
20 km, 10 km
C
18 km, 8 km
D
24 km, 14 km
E
None of these
» Explain it
Ans- Correct Option: A
Let the speed of a boy in still water be X km/h

And the speed of the current is given = 5 km/h

Downstream speed = (X + 5) km/h

Upstream speed = (X – 5) km/h

Let time be ‘t’ hours.

⇒ (X + 5) t = (X – 5) t
3
⇒ X + 5 = 3X – 15

⇒ 2X = 20

⇒ X = 10 km/h

Downstream speed = 10 + 5 = 15 km/h

Upstream speed = 10 – 5 = 5 km/h

Hence, option A is correct.

Q- 7 There are 3 points P, Q, and R in a straight line, such that point Q is equidistant from points P and R. A man can swim from point P to R downstream in 24 hours and from Q to P upstream in 16 hours. Find the ratio of the speed of man in still water to the speed of stream.
A
5 : 1
B
6 : 1
C
5 : 3
D
7 : 1
E
None of these
» Explain it
Ans- Correct Option: D
Let the speed of man in still water = x km/h

Speed of current = y km/h

Downstream speed = (x + y) km/h

Upstream speed = (x – y) km/h

Let PQ = QR = A and PR = 2A

So,

2A = 24 and A = 16
x + y x – y
By dividing both equations-

⇒ 2A (x – y) = 24
A (x + y) 16
⇒ 4x – 4y = 3x + 3y

⇒ x = 7
y 1
Required ratio = Speed of man in still water: Speed of current

⇒ 7 : 1

Hence, option D is correct.

Q-8Rohit can row a boat 65Km upstream and 130Km downstream in 23 hours, whereas he can swim 45Km upstream and 104Km downstream in 17 hours. Find the speed of the boat in still water and the speed of the stream.
A
4km/h, 9km/h
B
8 km/h, 5 km/h
C
9 km/h, 4 km/h
D
5 km/h, 8 km/h
E
10 km/h, 3 km/h
» Explain it
Ans- Correct Option: C
Upstream, U = Speed of boat – speed of the stream

Downstream, D = Speed of boat + speed of the stream

65 + 130 = 23
U D
45 + 104 = 17
U D
By solving the above two equations, we will get

U = Speed of boat – speed of stream = 5

D = Speed of boat + speed of stream = 13

Thus, Speed of the boat = 9 and speed of the stream = 4

Hence, option C is correct.

Q- 9 If the ratio of the speed of a boat in upstream and the speed of the stream is 8 : 1. If the boat can travel 500 km downstream in 20 hours then find the total distance traveled by boat in still water in the same time?
A
425 km
B
459 km
C
441 km
D
450 km
E
None of these
» Explain it
Correct Option: D
Let the speed of boat in upstream = 8x km/hr

And the speed of the stream = x km/hr

Speed of boat in downstream = 500 = 25 km/hr
20
Let the speed of boat in still water = p km/hr

Then, p + x = 25 km/hr ……….(i)

P – x = 8x , p = 9x ………..(ii)

Put the value of p in the equation (i)

10x = 25, x = 2.5

From the equation (ii) speed of boat in still water = 9x = 9 × 2.5 = 22.5 km/hr

The total distance travelled by the boat in still water in 20 hours = 450 km

Ans-  D is correct.

General Science Notes

MyNotesAdda.com will update many more new pdf and study materials and exam updates, keep Visiting and share our post, So more people will get this.

This PDF is not related to MyNotesAdda and if you have any objection over this pdf , you can mail us at zooppr@gmail.com