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Today we are sharing an important notes pdf in Advance Maths By Rakesh Yadav PDF Free Download in Hindi  SSC NOTES like SSC CGL, BANK, RAILWAYS,  RRB NTPC, LIC AAO, and many other exams.  is very important for any competitive exam and this for SSC, BANK, AND RAILWAYS is very useful for it. this FREE PDF will be very helpful for your examination. Advance Maths By Rakesh Yadav PDF Free Download in Hindi

Advance Maths By Rakesh Yadav PDF Free Download in Hindi for SSC, BANK, AND RAILWAYS is very Simple and Easy. We also Cover Basic Topics like math,  etc, and study materials including previous Year Question Papers, Current Affairs, Important Formulas, etc for upcoming Banking, UPSC, and SSC CGL Exams. Our PDF will help you to upgrade your marks in any competitive exam.

### Section-II: GEOMETRY | Advanced Maths Syllabus

• LINES AND ANGLES
• TRIANGLES
• CENTRES OF A TRIANGLE
• TRIANGLES (Congruences and Similarity)
• CIRCLES

### Section-III: MENSURATION | Advanced Maths Syllabus

• MENSURATION – 2D
• MENSURATION  – 3D
• PRISM & PYRAMID

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### Section-IV: ALGEBRA | Advanced Maths Syllabus

• INDICES AND SURDS
• ALGEBRAIC IDENTITIES

### Section-V: TRIGONOMETRY | Advanced Maths Syllabus

• TRIGONOMETRIC CIRCULAR MEASURE AND ANGLES
• TRIGONOMETRIC RATIOS
• TRIGONOMETRIC IDENTITIES
• MAXIMUM MINIMUM VALUE OF TRIGONOMETRIC FUNCTIONS
• HEIGHTS AND DISTANCES

### Previous Year Advance Maths Questions For SSC CGL TIER – 2

#### Q.1. A sum of Rs. 25000 amounts to Rs. 31000 in 4 years at the rate of simple interest what is the rate of interest?

(a) 3%

(b) 4%

(c) 5 %

(d) 6 %

(e) None of these

Q.2. Kamla took a loan of Rs. 2400 with simple interest for as many years as the rate of interest. If she paid Rs. 864 as interest at the end of the loan period, what was the rate of interest?

(a) 3.6

(b) 6

(c) 18

(d) cannot be determined

(e) None of these

Q.3. What is the present worth of Rs. 264 dues in 4 years at 10% simple interest per annum?

(a) 170.20

(b) 166

(c) 188.57

(d) 175.28

Q.4. A sum fetched a total simple interest of Rs. 8016.25 at the rate of 6 p.c.p.a in 5 years what is the sum?

(a) 24720.83

(b) 26730.33

(c) 26720.83

(d) 26710.63

(e) None of these

Q.5.  8. Rs. 800 becomes Rs. 956 in 3 years at a certain rate of simple interest. If the rate of interest is increased by 4%, what amount will Rs 800 become in 3 years?

(a) 1020.80

(b) 1025

(c) 1052

Q. 6.  The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is –

a.   74

b.   78

c.   80

d.   90

Q.7.   The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __

a.   3

b.   6

c.   9

d.   8.2

Q.8.  √6+√6+√6+… is equal to –

a. 2

b. 5
c. 4
d. 3

Q.9. The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –

a. 24

b. 32

c. 40

d. 28

Q.10. When (6767 +67) is divided by 68, the remainder is-

a. 1

b. 63

c. 66

d. 67

### Important Maths questions for SSC CGL Exam

1.   The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is –

a.   74

b.   78

c.   80

d.   90

Ans : Let the numbers be x and y .

We know   xy = 1575

And  x/y = 9/7

We know   xy/x/y = 1575/9/7

We know    y2  = 1225

We know  y = 35 and x = 45

We know   The sum of the numbers = 45+35

= 80

2.   The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __

a.   3

b.   6

c.   9

d.   8.2

Ans : (81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)

= 314.4+5.4-16.8-1

= 32

= 9

3.  √6+√6+√6+… is equal to –

a. 2
b. 5
c. 4
d. 3

Ans : Let √6+√6+√6+…. be x.
We know x =√6+x
We know x2 = 6+x
We know x2 – x – 6 = 0
We know (x-3) (x+2) = 0
We know x = 3

4.   The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –

a.   24

b.   32

c.   40

d.   28

Ans : Let the consecutive odd numbers be x and (x+2)

We know that x2 + (x + 2)2 = 394

We know   x2 + x2 + 4x + 4 = 394

We know   2 x2 +4x – 390 = 0

We know   x2 + 2x – 195 = 0

We know  (x +15) (x-13) = 0

We know   x = 13

We know    Required sum = 13 +15 =28

5.   When (6767 +67) is divided by 68, the remainder is-

a.   1

b.   63

c.   66

d.   67

Ans:  (6767+ 67) = 67(6766 + 166)

As 66 is an even number

We know   6766 is an even number

We know   (6766 + 1) is perfectly divisible by (67 + 1)

i.e. 68

We know   The remainder = 66

6.   In a division sum, the divisor is 4 times the quotient and twice the remainder. If a and b are respectively the divisor and the dividend then-

a.   4b-a2 /a  =3

b.   4b-2a /a2 =2

c.   (a+1)2 = 4b

d.   A(a+2)/b = 4

Ans : As  divisor is a, and dividend is b.

We know    Quotient = a/4

And Remainder = a/2

We know    b = a * a/4 + a/2

We know    4b = a2 + 2a

We know    a(a+2)/b = 4

7.   If 738 A6A is divisible by 11, then the value of A is-

a.   6

b.   3

c.   9

d.   1

Ans :  As 738A6 A is divisible by 11.

We know    A + A + 3 = 6 + 8 + 7

We know    A = 9

8.   The east positive integer that should be subtracted from 3011 * 3012 so that the difference is perfect square is-

a.   3009

b.   3010

c.   3011

d.   3012

Ans :  We know that 3011 * 3012 = 3011 (3011 + 1)

= (3011)2 + 3011

We know    Required least number = 3011

9.   P, Q, R are employed to do a work for Rs. 5750. P and Q together finished 19/23 of work and Q and R together finished 8/23 of work. Wage of Q, in rupees, is-

a.   2850

b.   3750

c.   2750

d.   1000

Ans :  Work done by Q = 19/23 + 8/23 – 1

4/23

We know   Wage of Q = 4/23 * 5750

= Rs. 1000

10.  A can do a piece of work in 24 day, B in 32 days and C in 64 days. All begin to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. How many days did the work last?

a.   15

b.   20

c.   18

d.   30

Ans : Work done by A = 6/24 = ¼

Work done by B = (x-6)/32
(where x is no. of days in which work is competed)

We know that ¼ + x – 6/32 + x/64 = 1
We know 16 + 24 – 12 + x /64 = 1
We know 3x + 4 = 64
We know x = 60/3 = 20 days

General Science Notes